m(\(Ca Cl_{2}\))=535 g
m(Cl)=?
The molar mass of \(CaCl_{2}\) = 40.08 + 2 35.45 = 110.98
The atomic mass of Cl: 35.45 ( you can see it in the Periodic table)
110.98 g \(CaCl_{2}\)- 35.45 2 g Cl
535 g \(CaCl_{2}\) - x g Cl
Proportion:
110.98 : 535 = (35,45 2) : x
x = 535 35.45 * 2 / 110.98 = 37,931.5/110.98 = 341.79 g
Answer: m(Cl)=341.79 g
