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Answered

The chemical equation for the combustion of acetylene (C2H2) is given below.


mc021-1.jpg


What volume of oxygen at STP is required for the complete combustion of 100.50 mL of C2H2?

201 mL

201.00 mL

251 mL

251.25 mL

Verified Answer :

taskmasters

The balanced reaction would
be:


C2H2 + 5/2O2 = 2CO2 + H2O


We are
given the amount of acetylene in the reaction. This will be
the starting point of our calculation. We use the ideal gas equation to find
for the number of moles.


n = PV /
RT = 1.00(.1005 L) / (0.08206 atm L/mol K
) 273.15 K

n= 4.4837 x 10^-3 mol C2H2

4.4837 x 10^-3 mol C2H2 (5/2 mol O2/ 1 mol C2H2) = 0.0112 mol O2


V =
nRT/P = 0.0112 mol O2 x 273.15 K x 0.08206
atm L/mol K / 1 atm
V=0.25125 L or 251.25 mL

transitionstate

Answer:

                251.25 mL of O₂

Solution:

The balance chemical equation is as follow,

                             2 C₂H₂  +  5 O₂     →     4 CO₂  +  2 H₂O

As we know if the gas is acting ideally then 1 mole of any gas at standard temperature and pressure it will occupy exactly 22.4 L or  22400 mL of volume.

Keeping this in mind according to equation,

     44800 mL (2 mol) of C₂H₂ required  =  112000 mL (5 mol) of O₂

So,

                    100.50 mL of C₂H₂ will require  =  X mL of O₂

Solving for X,

                      X =  (100.5 mL × 112000 mL) ÷ 44800 mL

                      X  =  251.25 mL of O₂

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