Answer : The molar volume of the gas will be, 44.82 L
Solution :
Using ideal gas equation,
\(PV=nRT\)
where,
n = number of moles of gas = 1 mole
P = pressure of the gas = 0.5 atm
T = temperature of the gas = 273 K
R = gas constant = 0.0821 Latm/moleK
V = volume of the gas.
Now put all the given values in the above equation, we get the molar volume of the gas.
\((0.5atm)\times V=(1mole)\times (0.0821Latm/moleK)\times (273K)\)
\(V=44.82L\)
Therefore, the molar volume of the gas will be, 44.82 L
