A bag of jelly beans contains 24 jellybeans of different colors. There are 6 blue, 5 yellow, 10 green, and 3 black jellybeans. What is the probability of drawing a green jellybean, eating it, and then drawing another green jellybean?2. A bag of jelly beans contains 24 jellybeans of different colors. There are 6 blue, 5 yellow, 10 green, and 3 black jellybeans. What is the probability of drawing a green jellybean, eating it, and then drawing another green jellybean? (please show all work.)
the chances of getting a green jelly bean is 10 out of 24, if you eat it then the chances of pulling another green jelly bean would be 9 out of 23
Answer: The answer is 16.30%.
Step-by-step explanation: Given that there is a bag of jelly beans in which
Total number of jelly beans = 24,
number of blue jelly beans = 6,
number of yellow jelly beans = 5,
number of green jelly beans = 10
and
number of black jelly beans = 3.
According to the question, first we draw a green jelly bean, ate it, and then again draw another green jelly bean.
Therefore, the probability of doing so is given by
\(p=\dfrac{10}{24}\times \dfrac{9}{23}=\dfrac{90}{552}=0.1630=16.30\%.\)
Thus, the required probability is 16.30%.