Answer:
Period = 4.5 seconds
Frequency = 0.22 hertz.
Step-by-step explanation:
Given : 10-pound weight oscillating (as a pendulum) on a 5-meter-long rope.
To find : What is the period and frequency.
Solution :
The formula to find time when length is given,
\(T=2\pi\sqrt{\frac{L}{g}}\)
where,T is the time period , L is the length and g is the acceleration due to gravity
L= 5 m and g=9.8 m/s
Substitute in the formula,
\(T=2\pi\sqrt{\frac{5}{9.8}}\)
\(T=2\pi\sqrt{0.510}\)
\(T=2\times 3.14\times 0.714\)
\(T=4.483\)
The time period is approx 4.5 seconds.
\(\text{Frequency}=\frac{1}{\text{Period}}\)
\(\text{Frequency}=\frac{1}{4.5}\)
\(\text{Frequency}=0.22\text{hertz}\)
Therefore, Period = 4.5 seconds
Frequency is 0.22 hertz.
