Answer: pOH= 4.06
pH= 9.94
\([H^+]=1.14\times 10^{-10}M\)
Explanation: pOH is the negative logarithm of \(OH^-\) concentration.
pH is the negative logarithm of \(H^+\) concentration.
\(pOH=-log[OH^-]\)
\(pOH=-log[8.6\times 10^{-5}]=4.06\)
2) \(pH+pOH=14\)
\(pH=14-4.06\)
\(pH=9.94\)
3) \(pH=-log[H^+]\)
\(9.94=-log[H^+]\)
\([H^+]=1.14\times 10^{-10}M\)
