Verified Answer :

mariamikayla

\(6x-2y=33 \\\\ 6x=33+2y \\\\ \boxed{x=\frac{2y+33}{6}} \\\\ 4x+3y=9 \\\\ 4*\frac{2y+33}{6}+3y=9 \\\\ 2*\frac{2y+33}{3}+3y^{(3}=9^{(3} \\\\ 2(2y+33)+9y=27 \\\\ 4y+66+9y=27 \\\\ 13y=27-66 \\\\ 13y=- 39 \\\\ \boxed{y=-\frac{39}{13}=-3} \\\\ x=\frac{2*(-3)+33}{6} \\\\ x=\frac{-6+33}{6} \\\\ x=\frac{27}{6} \\\\ \boxed{x=\frac{9}{2}}\)

Johnweshas

To find the variables of the equations, use systems of equations.

First get rid of one variable. Let's get rid of the y by multiplyin both equations nad then adding them.
\((6x-2y=33)3\)
\((4x+3y=9)2\)

\(18x-6y=99\)
\(8x+6y=18\)
\(26x=117\)

Solve for x:
\(\frac{26x}{26} = \frac{117}{26}\)
\(x=4.5\)

Now you have x! Plug x into one quation and solve for y:
\(6(4.5)-2y=33\)
\(27-2y=33\)
\(\frac{-2y}{-2} = \frac{6}{-2}\)
\(y=-3\)

\(x=4.5, y=-3\)

Related Questions