A solution of ammonia and water contains 1.80×1025 water molecules and 7.00×1024 ammonia molecules. How many total hydrogen atoms are in this solution?
1 water molecule contains 2H atoms H atoms in 4.2010^25 water molecules = 8.410^25 H atoms 1 NH3 molecule contains 3 H atoms H atoms in 6.0010^24 NH3 atoms = 36.0010^24 = 1.810^16 H atoms.
Total H atoms = 8.410^25 + 1.810^25 = 1.02*10^16 H atoms
Answer:
6.40x10²⁵ hydrogen atoms
Explanation:
The solution contains:
We need to calculate the total of hydrogen atoms (H) in the solution.
Lets now calculate the number of hydrogen atoms in the solution:
total H atoms = (H atoms in water molecules) + (H atoms in ammonia molecules)
total H atoms = (2 x 1.80x10²⁵) + (4 x 7.00x10²⁴) =
total H atoms = 3.60x10²⁵ + 2.80x10²⁵ = 6.40x10²⁵