Verified Answer :

Panoyin

\(_{3}P_{0} = \frac{3!}{(3 - 0)!}\)
\(_{3}P_{0} = \frac{3!}{3!}\)
\(_{3}P_{0} = \frac{3 * 2 * 1}{3 * 2 * 1}\)
\(_{3}P_{0} = 1\)

The answer is B.

Answer:

Option B. 1

Step-by-step explanation:

We have to find the value of P(3, 0)

We have to find the value of given permutation \(^{3}P_{0}\)

Since we know \(^{a}P_{b}=\frac{a!}{(a-b)!}\)

Here a = 3

b = 0

\(^{3}P_{0}=\frac{3!}{(3-0)!}\)

\(=\frac{3!}{3!}=1\)

Therefore, option B. 1 is the answer.

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