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Lakshmi has a sample of ammonium nitrate (NH4NO3) that has a mass of 40.10 g. She knows that the molar mass of NH4NO3 is 80.0432 g/mol. To the correct number of significant digits, how many moles of NH4NO3 does the sample contain?

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Hagrid

Lakshmi has a sample of ammonium nitrate (NH4NO3) that has a mass of 40.10 g. She knows that the molar mass of NH4NO3 is 80.0432 g/mol. Divide 40.10 grams to 80.0432 g/mol and you will get 0.5010 moles.

The correct number of significant digits and moles of NH4NO is 0.500979 mol.

The molar mass is the mass of 1 mole of the substance.

  • Ammonium nitrate, (NH4NO3), a salt of ammonia and nitric acid, is used widely in fertilizers and explosives. The commercial-grade contains about 33.5 percent nitrogen, all of which is in forms utilizable by plants; it is the most common nitrogenous component of artificial fertilizers.
  • If the molar mass of nh4no3 is 80.0432 g/mol, that means there are 80.0432 g of substance in 1 mole. The question is how many moles is 40.10 g of substance.

80.0432 g : 1 mol = 40.10 g : x mol

By crossing the products:

Therefore:

x · 80.0432 g = 1 mol · 40.10 g

⇒ x = 40.10 ÷ 80.0432 mol

The correct number of significant digits and moles of NH4NO is 0.500979 mol.

Learn more about  ammonium nitrate

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