Answer:
\(AB-C^2\) in simplest form:
\(3x^3+x^2+6x-9\)
Step-by-step explanation:
The distributive property says that:
\(a \cdot (b+c) =a\cdot b+ a\cdot c\)
Given that:
The variables A, B, and C represent polynomials
Where,
\(A = x^2\)
\(B = 3x+2\)
\(C = x-3\)
We have to find the \(AB-C^2\)
then;
\(AB-C^2\) =\((x^2)(3x+2)-(x-3)^2\)
Apply the distributive property :
\((3x^3+2x^2)-(x-3)^2\)
⇒\(3x^3+2x^2-(x^2+9-6x)\)
Remove the bracket, we have;
\(3x^3+2x^2-x^2-9+6x\)
Combine like terms;
\(3x^3+x^2+6x-9\)
Therefore, \(AB-C^2\) in simplest form: \(3x^3+x^2+6x-9\)
