Answered

Two urns each contain green balls and blue balls. Urn I contains 4 green balls and 6 blue balls, and Urn II contains 6 green balls and 2 blue balls. A ball is drawn at random from each urn. What is the probability that both balls are blue?




A2/51


B3/20


C1/10



D.4/153

Verified Answer :

caitlinnn

2/10+6/8=8/80=1/10

C.1/10

JeanaShupp

Answer: B. \(\frac{3}{20}\)


Step-by-step explanation:

Let A be the event that a blue ball is drawn from urn l and let B be the event that a blue ball is drawn from urn ll.

Then P(A)=\(\frac{\text{number of blue balls}}{\text{total balls}}\)

\(=\frac{6}{10}=\frac{3}{5}\)

and P(B)=\(\frac{\text{number of blue balls}}{\text{total balls}}\)

\(=\frac{2}{8}=\frac{1}{4}\)

As both the events are independent, thus the probability that both balls are blue =\(P(A)\times\ P(B)=\frac{3}{5}\times\frac{1}{4}=\frac{3}{20}\)


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