Verified Answer :

Answer: The density of glycerol will be \(1.26cm^3\)

Explanation:

Density is defined as the mass contained per unit volume.

\(Density=\frac{mass}{Volume}\)

Given : Mass of glycerol= \(4.10\times 10^3\) g

Volume of bromine =  3.25 L= \(3250cm^3\)  \((1L=1000cm^3)\)

Putting in the values we get:

\(Density=\frac{4.10\times 10^3g}{3250cm^3}=1.26g/cm^3\)

Thus density of glycerol will be \(1.26cm^3\)

mariejoepagaduan

The density of glycerol used in cosmetics and soaps is 1.26 g/cm³.

FURTHER EXPLANATION

Density is the measure of the compactness of a material. It is the mass per given volume. This can be expressed mathematically as:

\(Density = \frac{mass}{volume}\)  (equation 1)

To solve the problem, we first sort the given in the problem:

mass = 4.10 × 10³ g

volume - 3.25 L

The problem is asking for the density in units of g/cm³ which means that we must first convert the volume from liters to cm³.

\(volume \ (in \ cm^3) = 3.25 \ L \times \frac{1000 \ mL}{1 \ L} \times \frac{1 \ cm^3}{1 \ mL}\\volume \ (in \ cm^3) = 3250 \ cm^3\)

Now we can plug in the values of mass and volume into equation 1:

\(Density = \frac{4.10 \times 10^3 \ g}{3250 \ cm^3}\\\\Density = 1.2615 \frac{g}{cm^3}\)

Since the given in the problem both have 3 significant figures, the final answer must also have three significant digits only. Therefore,

\(\boxed {Density = 1.26 \frac{g}{cm^3}}\)

The density of glycerol is greater than 1, so when mixed with water it will sink.

LEARN MORE

  1. Learn more about Displacement Method brainly.com/question/11474085
  2. Learn more about Liquid Density brainly.com/question/11301218
  3. Learn more about Dimensional Analysis brainly.com/question/1557970

Keywords: Density, Mass, Volume, Unit Conversion

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