Answer:
Magnetic field strength, B = 5.95 Tesla
Explanation:
It is given that,
Length of wire, l = 0.36 m
It is moving perpendicularly through a magnetic field at a speed of, v = 0.21 m/s
Induced emf, E = 0.45 volts
The mathematical expression for induced emf is given by :
\(E=\dfrac{d\phi}{dt}=Blv\)
\(\dfrac{d\phi}{dt}\) is the rate of change of magnetic flux,
B is magnetic field
So, \(B=\dfrac{E}{lv}\)
\(B=\dfrac{0.45}{0.36\times 0.21}\)
B = 5.95 Tesla
Hence, this is the required solution.
