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What would be the volume in liters of an ideal gas, if a 0.111 mole sample of the gas had a temperature of 1130 degrees Celsius at a pressure of 5.45 atmospheres? (The ideal gas constant is 0.0821 L•atm/mol•K.)


0.43 liters


1.43 liters


1.89 liters


2.35 liters

Verified Answer :

Hagrid

It is implied that the gas is ideal. The given parameters are: P=5.45, T=1130degC, n=0.111moles and  ideal gas constant is 0.0821 L•atm/mol•K. The Ideal gas equation is PV=nRT. Note: All units are consistent. Plug in the values and you get an answer of 2.35L. 

Answer: Option (d) is the correct answer.

Explanation:

The given data is as follows.

      n = 0.111 mole,           T = 1130 degrees Celsius = 1130 + 273 = 1403 K

       P = 5.45 atm,            V = ?

       R = 0.0821 L atm/mol K

Using the ideal gas equation, we can calculate the volume as follows.

                                    PV = nRT

 or,                                V = \(\frac{nRT}{P}\)

                                         = \(\frac{0.111 mole \times 0.0821 L atm/mol K \times 1403 K}{5.45 atm}\)

                                         = \(\frac{12.786 L}{5.45}\)

                                         =  2.346 L

or,                                     = 2.35 L (approx)

Thus, we can conclude that volume of the ideal gas is 2.35 liters.

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