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SananaAngnyajaff
SananaAngnyajaff SananaAngnyajaff
  • 08-06-2016
  • Chemistry
Answered

How many liters of propane gas (C3H8) will undergo complete combustion with 34.0L of O2 gas?

Verified Answer :

taskmasters
taskmasters taskmasters
  • 14-06-2016

The balanced chemical
reaction will be:

C3H8 + 5O2 = 3CO2 +4H2O

We are given the amount
of oxygen gas to burn the propane gas. This will be our starting point.

34.0 L O2 ( 1 mol O2 / 22.4 L O2 ) (1 mol C3H8 / 5 mol O2 ) ( 22.4 L C3H8 / 1 mol C3H8) = 6.8 L C3H8

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