Answer:
\(10\frac{1}{2}\)
Step-by-step explanation:
We are asked to add the given mixed fractions.
\(6\frac{4}{5}+3\frac{7}{10}\)
First of all, let us convert mixed fractions into improper fractions as:
\(6\frac{4}{5}\Rightarrow \frac{6\times 5+4}{5}=\frac{30+4}{5}=\frac{34}{5}\)
\(3\frac{7}{10}\Rightarrow \frac{3\times 10+7}{10}=\frac{30+7}{10}=\frac{37}{10}\)
\(6\frac{4}{5}+3\frac{7}{10}\Rightarrow \frac{34}{5}+\frac{37}{10}\)
Make a common denominator:
\(\frac{34\times 2}{5\times 2}+\frac{37}{10}\)
\(\frac{68}{10}+\frac{37}{10}\)
Combine numerators:
\(\frac{68+37}{10}\)
\(\frac{105}{10}\)
\(\frac{5\times 21}{5\times 2}\)
\(\frac{21}{2}\)
\(10\frac{1}{2}\)
Therefore, the simplified form of our given addition problem would be \(10\frac{1}{2}\) .
