Verified Answer :

1Jr

Second statement
2x2 + 8x – 24 = 0
Is true for the given conditions.

When x = -6
2x2 + 8x – 24 = 0
Becomes
2(-6)2 + 8(-6) – 24 = 0
2(36) - 48 - 24 = 0
72 - 48 - 24 = 0
0 = 0
Which is true.

When x = 2
2x2 + 8x – 24 = 0
Becomes
2(2)2 + 8(2) – 24 = 0
2(4) + 16 - 24 = 0
8 + 16 - 24 = 0
0 = 0

Which is true.

So 2x2 + 8x – 24 = 0 will be answer.

we know that

using a graph tool


let's proceed to graph each case to determine the roots

case 1) \(2x^{2} - 16x + 12 = 0\)

the roots are

\(x1=0.8\ x2=7.2\) ------> is not the solution

see the attached figure N \(1\)

case 2) \(2x^{2} +8x -24 = 0\)

the roots are

\(x1=-6\ x2=2\)

see the attached figure N \(2\) --------> is the solution

case 3) \(3x^{2} - 4x - 12 = 0\)

the roots are

\(x1=-1.4\ x2=2.8\)------> is not the solution

see the attached figure N \(3\)

case 4) \(3x^{2} +12x +36 = 0\)


the graph does not have x-intercepts

see the attached figure N \(4\) ------> is not the solution

therefore

the answer is

the solution is

\(2x^{2} +8x -24 = 0\)

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