deelorostenjm
Answered

What is the product of d – 9 and 2d2 + 11d – 4?


A=2d3 – 7d2 – 103d + 36

B=2d3 – 7d2 – 95d + 36

C=2d3 + 7d2 – 95d + 36

D=2d3 + 7d2 – 103d + 36

Verified Answer :

SociometricStar

Answer:

\(2d^3-7d^2-103d+36\)

A is the correct option.

Step-by-step explanation:

We have to find the product

\((d-9)(2d^2+11d-4)\)

Using the distributive property (term by term multiplication), we have

\(d\cdot2d^2+d\cdot11d+d\cdot(-4)-9\cdot2d^2-9\cdot11d-9\cdot(-4)\)

On multiplying, we get

\(2d^3+11d^2-4d-18d^2-99d+36\)

Combine like terms

\(2d^3-7d^2-103d+36\)

A is the correct option.

boffeemadrid

Answer:

(A)\(2d^3-7d^2-103d+36\)

Step-by-step explanation:

It is given that there are two functions that are \((d-9)\) and \(2d^2+11d-4\) and

We have to find the product of \((d-9)\) and \(2d^2+11d-4\), therefore we can write as:

\((d-9)(2d^2+11d-4)\)

\(2d^3-18d^2+11d^2-99d-4d+36\)

\(2d^3-7d^2-103d+36\)

which is the required product.

Thus, Option A is correct.

Related Questions