Answer: The product is \(10m^{-5}\)
Step-by-step explanation:
Since we have given that
\((5m^{-2})(2m^{-3})\)
We need to find the product:
\(5m^{-2}\times 2m^{-3}\\\\\\=\dfrac{5}{m^2}\times \dfrac{2}{m^3}(\because a^{-m}=\dfrac{1}{a^m})\\\\\\=\dfrac{5\times 2}{m^{2+3}}\\\\\\=\dfrac{10}{m^5}\)
Hence, the product is \(\dfrac{10}{m^5}=10m^{-5}\)
