Greg is in a car at the top of a roller-coaster ride. The distance, d, of the car from the ground as the car descends is determined by the equation d = 144 – 16t2, where t is the number of seconds it takes the car to travel down to each point on the ride. For which interval of time is Greg’s car moving in the air?
Answer:
It takes 3 seconds over the interval [0,3]
Step-by-step explanation:
To find when the roller coaster reaches the ground, find when d=0.
\(0=144-16t^2\)
To solve divide each term by 16 and factor:
\(\frac{0}{16}=\frac{144}{16} -\frac{-16t^2}{16} \\0= 9 - t^2\\0=(3-t)(3+t)\)
Solve for t by setting each factor to 0.
t-3=0 so t=3
t+3=0 so t=-3
This means the car is in the air from 0 to 3 second.
The time interval will be 0<t<3 or (0, 3)
A interval is a set of real numbers that contains all real numbers lying between any two numbers of the set.
Given:
d = 144 – 16t²
Now,
d>0
144 – 16t²>0
144>16t²
144/16>t²
9>t²
t<±3
Since, time can't be negative.
So, t<3
Hence, the interval for which Greg’s car moving in the air is, 0<t<3 or (0, 3).
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