The given function is
f(x)= log 10 x
Taking base as 10
\(y=\log_{10}10 +\log_{10}x\)→→Using the property of, log a b= log a + log b
→y = 1 + \(\log_{10}x\) as, \(\log_{10}10=1\)
we have to approximate the value of y in the equation
→10 y = 6
→y=\(\frac{6}{10}\)
\(\frac{6}{10}\)= 1 + \(\log_{10}x\)
\(\log_{10}x\) = \(\frac{-4}{10}\)
x= \((10)^{\frac{-4}{10}}\)=\((10)^{-0.4}\)=0.398
Solving graphically,
we get , x= 0.398 for , y= \(\frac{6}{10}\)=.6
