Verified Answer :

TSO

\(4x^3 + 8x^2 - 25x - 50 = \\ 4x^2(x + 2) - 25(x + 2)=\\ (4x^2 - 25)(x+2)=\\\\ \boxed{\bf{(2x - 5)(2x + 5)(x+2)}}\)

Answer:

The factored form is (x+2)(2x+5)(2x-5)

Step-by-step explanation:

The given expression which we need to factor is \(4x^3+8x^2-25x-50\)

We can factor it by grouping method.

Make groups as shown below.

\((4x^3+8x^2)+(-25x-50)\)

Take GCF from each groups

\(4x^2(x+2)-25(x+2)\)

Factored out the common terms

\((x+2)(4x^2-25)\)

Now, we can further factored \(4x^2-25\) using the difference of squares formula \(a^2-b^2=(a+b)(a-b)\)

Writing in perfect square form

\((x+2)((2x)^2-5^2)\)

Using the difference of square formula

\((x+2)(2x+5)(2x-5)\)

Thus, the factored form is (x+2)(2x+5)(2x-5)