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A dump truck accelerates uniformly from a resting position to a velocity of 35 m/s north in 20 seconds. What is the displacement?


a.) 1.75 m north

b.) 61.25 m north

c.) 350 m north

d.) 700 m north

Verified Answer :

metchelle

As this is a straight-line motion problem, the following formulas will be used to solve for acceleration, which is used to solve for displacement:

Vf = Vi + a  t
s = Vi t  + 1/2 (at^2)

Where: Vf = final velocity
Vi = initial velocity
a = acceleration
t = time
s = displacement

Using eq.1 :

35 m/s = 0 m/s + a  20 s
a = 35 / 20
a = 1.75 m/s^2

Using eq.2:

s = 0 20 + 1/2 (1.75 20^2)
s = 350 m

Therefore, the correct answer is C.

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