If y varies directly as x, and y is 48 when x is 6, which expression can be used to find the value of y when x is 2?
It is y= 8x
As given, y varies directly as x and y is 48 when x is 6.
So from the equation we can justify it.
When x=6
y= 8(6) = 48
Now, if x=2
y = 8(2)
y = 16
Answer:
y is 16
Step-by-step explanation:
If y varies directly as x, and y is 48 when x is 6, find the value of y when x is 2
When y varies directly as x then \(y=kx\)
where k is the constant of proportionality
y is 48 when x is 6, plug in the value and find out k
\(y=kx\)
\(48=k(6)\)
Divide both sides by 6
\(k=8\)
The equation y=kx becomes
\(y=8x\)
find the value of y when x is 2
\(y=8(2)= 16\)
So the value of y is 16