Human fat has a density of 0.918 g/cm^3. How much volume (in cm^3) is gained by a person who gains 10.1 lbs of pure fat?
Density is a physical property which describes the mass of a substance per unit of volume of the substance. It is expressed as Density = m / V and it has units like g/cm^3. We use the density given to solve the problem.
10.1 lbs (1 kg/2.2 lb)(1000 g / 1kg) / 0.918 g / cm^3 = 5001 cm^3
Answer: The volume of human fat is \(4990.52cm^3\)
Explanation:
We are given:
Mass of human fat = 10.1 pounds
To convert the given mass grams, we use the conversion factor:
1 pound = 453.592 g
So, \(10.1 pounds=10.1\times 453.592=4581.3g\)
To calculate volume of a substance, we use the equation:
\(Density=\frac{Mass}{Volume}\)
Putting values in above equation, we get:
\(0.918g/cm^3=\frac{4581.3g}{\text{Volume of human fat}}\\\\\text{Volume of human fat}=4990.52cm^3\)
Hence, the volume of human fat is \(4990.52cm^3\)