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Wyatt’s eye-level height is 120 ft above sea level, and Shawn’s eye-level height is 270 ft above sea level. How much farther can Shawn see to the horizon? Use the formula d = square root of 3h/2, h>0 with d being the distance they can see in miles and h being their eye-level height in feet.

Verified Answer :

metchelle

Using the formula given: d = √(3h/2)

We simply substitute the given values of h into the equation and compare the results.

For Wyatt where h = 120:
d = √(3(120)/2)
d = 13.42 miles

For Shawn where h = 270:
d = √(3(270)/2)
d = 20.12 miles

Since the question asks for how much farther can Shawn see, we subtract the results:

20.12 - 13.42 = 6.7

Therefore, Shawn can see 6.7 miles farther.

calculista

Let

d-------> is the distance they can see in miles

h-------> is the eye-level height in feet

we know that

The formula to find the distance d is equal to

\(d=\sqrt{\frac{3h}{2}}\)

Step \(1\)

Find the distance d for Wyatt’s eye-level

\(h=120 ft\)

\(d=\sqrt{\frac{3*120}{2}}\)

\(d=\sqrt{180}\)

\(d=13.42\) \(miles\)

Step \(2\)

Find the distance d for Shawn’s eye-level

\(h=270 ft\)

\(d=\sqrt{\frac{3*270}{2}}\)

\(d=\sqrt{405}\)

\(d=20.12\) \(miles\)

Step \(3\)

Subtract the distance d for Shawn’s eye-level from the distance d for Wyatt’s eye-level

\(=20.12-13.42\\\)

\(=6.70\) \(miles\)

therefore

the answer is

Shawn can see \(6.7\) \(miles\) farther

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