Answer : The correct option is, (a) 1.05 liters
Solution :
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
\(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\)
where,
\(P_1\) = initial pressure of gas = 255 kpa
\(P_2\) = final pressure of gas = 805 kpa
\(V_1\) = initial volume of gas = 2 L
\(V_2\) = final volume of gas = ?
\(T_1\) = initial temperature of gas = \(45^oC=273+45=318K\)
\(T_2\) = final temperature of gas = \(255^oC=273+255=528K\)
Now put all the given values in the above equation, we get the final volume of gas.
\(\frac{255kpa\times 2L}{318K}=\frac{805kpa\times V_2}{528K}\)
\(V_2=1.05L\)
Therefore, the final or new volume of gas will be, 1.05 liters
