5x^2+19x+12 factor the polynomial
Δ = 19^2 - 4512 => Δ = 121 => \(\sqrt{delta}\) = 11;x1 = -0.8; x2 = -3;5x^2+19x+12 = 5( x + 0.8)( x + 3) = ( 5x + 4)( x + 3);
Answer:
(x−3)(5x−4)
Step-by-step explanation: