Verified Answer :

\((x+3)^{2} + (y-2)^{2} =9\)

Working;
From the general equation of a circle;
\((x-h)^{2} + (y-k)^{2} = r^{2}\)
This gives;
\((x--3)^{2}+ (y-2)^{2} = 3^{2}\)
This gives;
\((x+3)^{2} + (y-2)^{2} =9\)