The volume of a square pyramid is
\(V=( \frac{1}{3}) b^{2} h\)
where b is the length of the base and h is the height
So plugging the numbers into the formula,
\(V=( \frac{1}{3}) b^{2} h\)
\(V=( \frac{1}{3}) (219.8m)^{2} (174.34m)\)
\(V=( \frac{1}{3}) (48312.04m^{2}) (174.34m)\)
\(V=( \frac{1}{3}) (8422721.0536m^{3})\)
\(V=2807573.68453m^{3}\)
the question says to the nearest cubic meter so the answer rounds up to
\(V=2807574m^{3}\)
The answer is \(V=2807574m^{3}\)
