The "Ideal Gas Law Equations" is
\(PV=nRT\)
P= Pressure (in Pascals)
V=Volume (in Liters)
n=amount, or number (in moles)
R= 8.3145 \(\frac{Pascals*Liters}{Moles*Kelvin}\) or \(\frac{PaL}{molK}\)
T= Temperature (In Kelvin)
\(P= \frac{nRT}{V}\)
Plug into the equation and you're good!
\(P=\frac{nRT}{V}\)
\(P =\frac{(5mol)(8.3145)(286K)}{2L}\)
\(P=5944.8675Pa\)
If your teacher cares about sig figs,
2 sig figs (significant figures)
\(P=5900Pa\)
For other units of pressure,
1 atm = 760 mmHG = 760 Torr = 101326 Pa = 1.01325 bar
