\(\,\,\, \,\,\, 8.32\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x\\ 2C_4H_1_0+9O_2\to 8CO_2+10H_2O \\ \,\,\, \,\,\,\,\,58\cdot2\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,44\cdot8 \\ \\ \frac{8.32}{58} = \frac{x}{44} \\ \\ x= \dfrac{8.32\cdot44\cdot8}{58\cdot2} =25.2\,\,g\)
Answer: 25.2 g.
