A force of 1500 pounds drags a truck 40 feet in 20 seconds. How much work is accomplished? How much power was required?
Answer:
The work done and power are 60000 Pounds-feet and 3000 Pounds-feet/sec.
Explanation:
Given that,
Force F = 1500 pounds
Distance d = 40 feet
Time t = 40 sec
Work done :
The work done is the product of the force and distance.
The work done is defined as,
\(W = F \times d\)
Where, W = work
F = force
d = distance
Put the value into the formula of work
\(W= 1500\times40\)
\(W = 60000\ Pounds-feet\)
Power:
The power is equal to the work done divided by time.
The power is defined as,
\(P = \dfrac{W}{t}\)
Where, P = power
W = work
t = time
Put the value into the formula of power
\(P = \dfrac{60000}{20}\)
\(P=3000\ Pounds-feet/s\)
Hence, The work done and power are 60000 Pounds-feet and 3000 Pounds-feet/sec.