Verified Answer :

caylus

Hello,

a(1)=8
a(2)=18=8+10=8+8+2=28+2=28+2(2-1)
a(3)=30=18+12=28+2(2-1)+8+2(3-1)=38+2(1+2)
a(4)=44=a(3)+14=38+2(1+2)+8+2(4-1)=48+2(1+2+3)....

a(n)=n8+2(1+2+3+...+(n-1))
= 8n+2n(n-1)/2)=8n+n(n-1)=n²+7n

\(\boxed{a_{n}= n^2+7n}\)

n=1=>1²+71=8
n=2=>2²+72=4+14=18
n=3=>3²+73=9+21=30
n=4=>4²+74=16+28=44
...



abidemiokin

The nth term of the sequence will be Tn = n^2 + 7n

How to calculate the nth term of a sequence

Given the sequence of numbers expressed as:

8;18;30;44;

Their common difference will form an A P as shown:

10, 12, 14...

Next term  = preceding term  + 2

Next term = 14 + 2

Next term = 16

The next term of the squence will be 44 + 16 = 60

The nth term of the sequence will be Tn = n^2 + 7n

Learn more on nth term here: https://brainly.com/question/7882626

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