Jeanette's sister charges $5.50 per hour before 9:00 pm for babysitting and $8 per hour after 9:00 pm. She finished babysitting at 11:00 pm and earned $38. At what what time did she began babysitting?

Hey there! :D Jeanette's sister started at 5:00 PM. To get that answer, here's what I did: From 5-9 PM, she earned $22. That's because 5.50 x 4 = 22, then from 10-11, she charged $8 which is 8 x 2 = 16 + 22 = $38. Again, she started at 5 PM.

Hope it Helps and makes sense! :D

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bhoopendrasisodiya34 bhoopendrasisodiya34 · Answer 2 · 2022-01-13T07:29:51-05:00

Time is the duration during which any activity or work is performed. Jeanette's sister started 4 hours before the 9:00 pm which is 5:00 pm.

Given-

Jeanette's sister charges $5.50 per hour before 9:00 pm.

Jeanette's sister charges $8 per hour after 9:00 pm.

She finished babysitting at 11:00 pm

She earned total money $38.

What is time?

Time is the duration during which any activity or work is performed.

Total hour she worked after the 9:00 pm,

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Thus she worked total 2 hours after the 9:00 pm. She charges charges $8 per hour after 9:00 pm.Hence money earned by her in 2 hours after 9:00 pm ,

$=2\times8=16$

Thus money earned by her in 2 hours after 9:00 pm is $16. The money earned by her before the 9:00 pm is addition of money earned by her before 9:00 pm and after 9:00 pm. Let money earned by her before 9:00 pm is $x. Thus,

$x+16=38$

$x=38-16$

$x=22$

Thus the money earned by her before 9:00 pm is $22.

She charges $5.50 per hour before 9:00 pm. Hence the $22 charged by her in hours,

$=\dfrac{22}{5.50} =4$

Therefore, hence Jeanette's sister started 4 hours before the 9:00 pm which is 5:00 pm.

Learn more about the work and time here;

https://brainly.com/question/8536605