a panel of 6 judges is being selected from a group of 10 males and 10 females.What is the probability of selecting exactly 3 male?
Probability of selecting exactly 3 male is equals to
" Probability is defined as the ration of the number of favourable outcomes to the total number of outcomes."
Formula used
Probability = \(\frac{n(S)}{n(T)}\)
\(n(S) =\) Number of favourable outcomes
\(n(T)=\) Total number of outcomes
According to the question,
Total number of males \(=10\)
Total number of females \(=10\)
Number of judges for a panel to be selected \(=6\)
As per given condition ,
Total number of outcomes \(= 20\rm C_{6}\)
Number of selecting exactly 3 males for 6 judges \(= 10\rm C_3\times 10\rm C_3\)
Substitute the value in the formula to get the required probability,
Probability of selecting exactly 3 males \(= \frac{ 10\rm C_3\times 10\rm C_3}{20\rm C_{6}}\)
\(= \frac{120}{323}\)
Hence, the probability of selecting exactly 3 males is equals to \(\frac{120}{323}\).
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