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Find the standard form of equation of the line that passes through the points (5,-9) and (2,-3)

A2x-y=-1
B2x-3y=3
C2x+y=1
Dx+2y=1

Verified Answer :

apologiabiology

(5,-9) and (2,-3)
y-y1=m(x-x1)
m=slope
(x1,y1) is a given points

slope=(y2-y1)/(x2-x1)
(x,y)
slope=(-3-(-9))/(2-5)=6/-3=-2
y-y1=-2(x-x1)
y-(-3)=-2(x-2)
y+3=-2x+4
2x+y=1


C

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