Determine the volume of 2.00 M HCl(aq) solution required to completely neutralize 20.0 milliliters of 1.00 M NaOH(aq) solution.
Molarity is equal to the moles of solute over liters of
solvent. In getting the molarity of HCl, you must know the formula for two
solutions which is equal to M1V1 = M2V2. (2.00 M HCl)V1
= (20.0 milliliters) (1.00
M NaOH) and you have the volume of 10
millimeters of HCl.
The volume of the HCl solution required to neutralize 20 mL of 1.00 M NaOH is 10 mL
HCl + NaOH —> NaCl + H₂O
From the balanced equation above,
From the question given above, the following data were obtained:
CaVa / CbVb = nA / nB
(2 × Va) / (1 × 20) = 1
(2 × Va / 20 = 1
Cross multiply
2 × Va = 20
Divide both side by 2
Va = 20 / 2
Va = 10 mL
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