The generic equation of the line is:
\(y = mx + b\)
Where,
m: slope of the line.
b: cutting point with vertical axis.
The slope of the line is given by:
\(m =\frac{y2-y1}{x2-x1}\)
\(m =\frac{14-15}{10-0}\)
\(m =-\frac{1}{10}\)
The cutting point with the vertical axis is:
\(b=15\)
Therefore, the equation of the line is:
\(y =-\frac{1}{10}x + 15\)
Answer:
the equation that represents Emily’s situation is:
\(y =-\frac{1}{10}x + 15\)
