A 25.0-meter length of platinum wire with a cross-sectional area of 3.50 × 10^−6 meter^2 has a resistance

of 0.757 ohm at 20°C. Calculate the resistivity of the wire. [Show all work, including the equation and

substitution with units.]

Verified Answer :

Tareki

R= (rou L) / area
where R is the wire resistance
rou: resistivity of the wire material
L : wire length
A : cross section area of wire
by sub.
0.757= (rou
25)/ 3.510^-6
25
rou = 2.649510^-6
rou= 1.0598
10^-7 ohm.m

The resistivity of the plantinum wire is 1.06 × 10⁻⁷Ωm

Calculating Resistivity

From the question,

We are to determine the resistivity of the wire

Resistivity can be calculated from the formula

\(\rho = \frac{RA}{l}\)

Where \(\rho\) is the resistivity of the wire

R is the resistance

A is the cross-sectional area

and \(l\) is the length of the wire

From the given information,

R = 0.757 ohm (Ω)

A = 3.50 × 10⁻⁶ m²

\(l\) = 25.0 m

Putting the parameters into the formula, we get

\(\rho = \frac{0.757 \times 3.50 \times 10^{-6} }{25}\)

\(\rho = 0.10598 \times 10^{-6}\)

\(\rho = 1.0598 \times 10^{-7}\)

\(\rho \approx 1.06 \times 10^{-7} \ \Omega m\)

Hence, the resistivity of the plantinum wire is 1.06 × 10⁻⁷Ωm

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