Answer: Option (4) is the correct answer.
Explanation:
The electronic configuration of neon in ground state is \(1s^{2}2s^{2}2p^{6}\).
The electronic configuration of helium in ground state is \(1s^{2}\).
The electronic configuration of radon in ground state is \(Xe 4f^{14}5d^{10}6s^{2}6p^{6}\).
The electronic configuration of hydrogen in ground state is \(1s^{1}\).
Therefore, from the above electronic configurations it can be seen that only hydrogen has deficiency of 1 electron and rest all the elements have completely filled shells. So, in order to complete its octet hydrogen will readily accept one electron.
Therefore, hydrogen will attain a stable valence electron configuration by bonding with another atom.
