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An electron traveling with a speed of 2.50 × 10^6 meters per second collides with a photon

having a frequency of 1.00 × 10^16 hertz. After the collision, the photon has 3.18 × 10^−18 joule of

energy.

Calculate the original kinetic energy of the electron. [Show all work, including the equation and

substitution with units.]

Verified Answer :

Answer;

K.E =2.85 × 10⁻¹⁸ Joules.

Explanation;

  • Kinetic energy is the energy that keeps an object or a body in motion.
  • Kinetic energy is given by the formula 1/2 mv², where m is the mass of the particle or body in motion, and v is the velocity.

K.E = 1/2 mv²

  Mass of an electron = 9.11 × 10⁻³¹ Kg, velocity of the electron =2.5×10⁶ m/s

Thus, K.E = 1/2 (9.11 × 10⁻³¹ Kg) (2.5 × 10⁶ m/s)²

                 = 2.85 × 10⁻¹⁸ Joules.

Lanuel

The original kinetic energy of this electron is equal to 2.85 × 10⁻¹⁸ Joules.

Given the following data:

  • Velocity of an electron =2.5 × 10⁶ m/s.
  • Frequency = 1.00 × 10¹⁶ hertz.
  • Photon energy = 3.18 × 10⁻¹⁸ Joules.

Scientific data:

  • Mass of an electron = 9.11 × 10⁻³¹ Kg.

How to calculate kinetic energy?

Mathematically, kinetic energy can be calculated by using this formula:

K.E = 1/2 × mv²

Where:

  • K.E is the kinetic energy.
  • M is the mass.
  • V is the velocity.

Substituting the given parameters into the formula, we have;

K.E = 1/2 × 9.11 × 10⁻³¹ × (2.5 × 10⁶ m/s)²

K.E = 2.85 × 10⁻¹⁸ Joules.

Read more on kinetic energy here: brainly.com/question/1242059

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