Given:
114.32g of water
14.85oC is raised
to 18.00oC
Required:
Change in heat
energy
Solution:
This can be solved
through the equation H = mCpT
where H is the heat, m is the mass, Cp is the specific heat and T is the change in temperature.
The specific heat
of the water is 4.18 J/g-K
Plugging in the
values into the equation
H = mCpT
H = (114.32g) (4.18
J/g °C) (18 – 14.85)
H = 1,505.3 J
