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Answered

What is the minimum total energy released when

an electron and its antiparticle (positron)

annihilate each other?

(1) 1.64 × 10^–13 J (3) 5.47 × 10^–22 J

(2) 8.20 × 10^–14 J (4) 2.73 × 10^–22 J

Verified Answer :

Answer:

(1) \(1.64 \times 10^{-13} J\)

Explanation:

Energy released in this process is given by

\(Q = \Delta m c^2\)

here we have

\(\Delta m = 9.1 \times 10^{-31} kg\)

since here mass of two electrons converted into energy so we have

\(Q = 2(9.1 /times 10^{-31})(3\times 10^8)^2\)

\(Q = 1.64 \times 10^{-13} J\)

so here energy released is the energy of rest mass energy due to two charges i.e. electrons and positrons

onyebuchinnaji

The minimum total energy released when an electron and its antiparticle (positron) annihilate each other is 1.64 x 10⁻¹³ J.

What is the minimum total energy released?

The minimum total energy released when an electron and its antiparticle (positron) annihilate each other is calculated as follows;

E = Δmc²

where;

  • m is the mass of the two electrons
  • c is speed of light

E = (2 x 9.11 x 10⁻³¹) x (3 x 10⁸)²

E = 1.64 x 10⁻¹³ J

Learn more about energy here: https://brainly.com/question/25959744

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