\(2 C_{6}H_{6} + 15O_{2} ----->\ \textgreater \ 12CO_{2} + 6H_{2}O\)
\(mol of benzene = \frac{mass}{Mr}\)
= \(\frac{10.47g}{(6 * 12) (6 * 1) g/mol}\)
= 0.134 mol
mol of oxygen:
ratio of \(C_{6} H_{6} : O_{2}\)
= 2 : 15
= 1 : 7.5
: . mol of \(O_{2}\) = 0.134mol 7.5
= 1.01 mol
Mass of Oxygen = mol Mr
= 1.01 mol (162) g/mol
= 32.22g
Note: Mr is molar mass
