The length of a rectangle is represented by the function L(x) = 2x. The width of that same rectangle is represented by the function W(x) = 8x2 − 4x + 1. Which of the following shows the area of the rectangle in terms of x?


(L + W)(x) = 8x2 − 2x + 1

(L + W)(x) = 8x2 − 6x + 1

(L ⋅ W)(x) = 16x3 − 4x + 1

(L ⋅ W)(x) = 16x3 − 8x2 + 2x

Verified Answer :

Area of a rectangle = length width = (2x) \(8x^{2} - 4x + 1\) = \(16 x^{3} - 8 x^{2} + 2x\)

Answer: the last option

Answer:

Option D is correct.

\((L \cdot W)(x) = 16x^3-8x^2+2x\)

Step-by-step explanation:

Area of  rectangle(A) is given by:

\(A = l \cdot w\)

where

l is the length of rectangle and w is the width of the rectangle respectively.

As per the statement:

Length of a rectangle L(x) = 2x and

Width of a rectangle W(x) = \(8x^2-4x+1\)

Then by formula of area of rectangle:

\(A(x) = L(x) \cdot W(x) = (L \cdot W)(x)\)

Substitute the given values we have;

\((L \cdot W)(x) = (2x) \cdot (8x^2-4x+1)\)

Using the distributive property: \(a\ cdot (b+c) = a\cdot b+a\cdot c\)

\((L \cdot W)(x) = 16x^3-8x^2+2x\)

Therefore, the area of the rectangle in terms of x is:

\((L \cdot W)(x) = 16x^3-8x^2+2x\)