Verified Answer :

Willchemistry

\((4a^{4b} )^{2}\)

Apply exponent rule : \((a*b)^n = a^nb^n\)

\(4^2(a ^{4b})^2\)

\((a ^{4b} )^2\)

Apply exponent rule :

 \((a^b)^c= a ^{b*c}\)

\(= a ^{8b}\)

\(= 4^2 = 16\)

\(=\ \textgreater \ 16 a ^{8b}\)

hope this helps!

Answer:

The simplified expression is \(16a^{8b}\)  

Step-by-step explanation:

we need to simplify the expression \((4a^{4b})^{2}\)

\((4a^{4b} )^{2}\)  

Using exponent rule : \((a\times b)^{n} = a^{n}b^{n}\)

\(4^{2}(a ^{4b})^{2}\)

\(16(a ^{4b} )^2\)  

Apply exponent rule :

\((a^b)^c= a ^{b*c}\)

\((a ^{4b} )^2= a ^{8b}\)

\(16a^{8b}\)

Hence, simplified expression is  \(16a^{8b}\)

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