\(3 x^{2} + x + 10 = 0\)
\(x = \frac{-b(+or-) \sqrt{ b^{2} - 4ac } }{2a}\)
\(x = \frac{-1(+or-) \sqrt{ 1^{2} - 4(3)(10) } }{2(3)}\)
: . x = \frac{-1 + \sqrt{-119} }{6} OR \(x = \frac{-1 - \sqrt{-119} }{6}\)
Thus the roots or the solutions to this equation are imaginary because the discriminant \(\sqrt{-119}\) is negative and a negative number is undefined when rooted.
