Verified Answer :

That would be A.... when you divide the trinomial in bracket by the \(6x^{2}\) you will realize that the coefficient of the x is 3.  If you want me to send a picture of the division please indicate.

Answer:

3

Step-by-step explanation:

Given : \(\frac{18x^3+12x^2-3x}{6x^2}\)

To Find: What is the coefficient of x in the division

Solution:

\(\frac{18x^3+12x^2-3x}{6x^2}\)

On Dividing we

Quotient = 3x+2

Remainder = -3x

So, coefficient of x in quotient = 3

Thus the coefficient of x in the division \(\frac{18x^3+12x^2-3x}{6x^2}\) is 3

Hence Option A is correct